SQL challenge: Customer's Orders

Challenge: customer's orders (solution in white below)

SELECT customers.name, customers.email, sum(orders.price) as total_purchase FROM customers LEFT OUTER JOIN orders ON customers.id = orders.customer_id GROUP BY customer_id ORDER BY total_purchase DESC

Takeaway notes from a newbie:
To sort in descending order, use DESC

LEFT OUTER JOIN refers to LEFT as customers in this case (the first one listed). You need to put the table with more info on the left, and join it with the right. In this case we have customers who may not have placed any orders yet. So all orders have customers who placed them, but not all customers have placed orders. So you need orders to go on the left.